Golang strconv.AppendUint

last modified April 20, 2025

This tutorial explains how to use the strconv.AppendUint function in Go. We’ll cover unsigned integer to byte slice conversion with practical examples.

The strconv.AppendUint function appends the string representation of an unsigned integer to a byte slice. It’s efficient for building formatted output.

AppendUint is particularly useful when you need to build strings or byte slices containing numeric values without creating intermediate string objects.

Basic strconv.AppendUint Example

The simplest use of strconv.AppendUint appends an unsigned integer to a byte slice. Here we demonstrate basic usage with base 10 conversion.

basic_appenduint.go

package main

import ( “fmt” “strconv” )

func main() { buf := []byte(“Number: “) num := uint64(42)

buf = strconv.AppendUint(buf, num, 10)
fmt.Println(string(buf))

}

We start with a byte slice containing “Number: “. We append the string representation of 42 to it. The result is printed as a string.

Using Different Bases

strconv.AppendUint supports different numeric bases. This example shows hexadecimal, binary, and octal representations.

different_bases.go

package main

import ( “fmt” “strconv” )

func main() { num := uint64(255)

buf10 := strconv.AppendUint([]byte{}, num, 10)
buf16 := strconv.AppendUint([]byte{}, num, 16)
buf2 := strconv.AppendUint([]byte{}, num, 2)
buf8 := strconv.AppendUint([]byte{}, num, 8)

fmt.Println("Decimal:", string(buf10))
fmt.Println("Hexadecimal:", string(buf16))
fmt.Println("Binary:", string(buf2))
fmt.Println("Octal:", string(buf8))

}

We convert the same number (255) to different bases. Each conversion starts with an empty byte slice. The results show different string representations.

Building a Formatted String

This example demonstrates building a complex formatted string using multiple AppendUint calls and other append operations.

formatted_string.go

package main

import ( “fmt” “strconv” )

func main() { buf := []byte(“Values: “)

for i := uint64(1); i <= 5; i++ {
    buf = strconv.AppendUint(buf, i, 10)
    buf = append(buf, ' ')
}

fmt.Println(string(buf))

}

We start with “Values: " and append numbers 1 through 5 with spaces. The result is a single string built efficiently without temporary allocations.

Appending to Existing Data

This example shows how AppendUint can append to existing byte slices containing other data, preserving the original content.

existing_data.go

package main

import ( “fmt” “strconv” )

func main() { data := []byte{0x48, 0x65, 0x6c, 0x6c, 0x6f} // “Hello” in ASCII num := uint64(12345)

result := strconv.AppendUint(data, num, 10)
fmt.Println(string(result))

}

We start with a byte slice containing “Hello”. We append the number 12345 to it. The result combines the original bytes with the new numeric representation.

Performance Comparison

This example compares AppendUint with string concatenation to demonstrate its performance benefits.

performance.go

package main

import ( “fmt” “strconv” “time” )

func main() { const iterations = 100000 num := uint64(42)

// Using AppendUint
start := time.Now()
buf := []byte{}
for i := 0; i < iterations; i++ {
    buf = strconv.AppendUint(buf[:0], num, 10)
}
fmt.Println("AppendUint duration:", time.Since(start))

// Using string concatenation
start = time.Now()
s := ""
for i := 0; i < iterations; i++ {
    s = strconv.FormatUint(num, 10)
}
fmt.Println("FormatUint duration:", time.Since(start))

}

AppendUint is generally more efficient than string concatenation for building complex output. It avoids creating intermediate string objects.

Error Handling with Invalid Bases

While AppendUint doesn’t return errors, using invalid bases has defined behavior. This example explores edge cases.

invalid_bases.go

package main

import ( “fmt” “strconv” )

func main() { num := uint64(42)

// Valid base
buf10 := strconv.AppendUint([]byte{}, num, 10)
fmt.Println("Base 10:", string(buf10))

// Base 1 (invalid)
buf1 := strconv.AppendUint([]byte{}, num, 1)
fmt.Println("Base 1:", string(buf1))

// Base 36 (valid)
buf36 := strconv.AppendUint([]byte{}, num, 36)
fmt.Println("Base 36:", string(buf36))

// Base 37 (invalid)
buf37 := strconv.AppendUint([]byte{}, num, 37)
fmt.Println("Base 37:", string(buf37))

}

Bases outside 2-36 range fall back to base 10. This ensures the function always produces valid output without panicking.

Practical Example: Building a CSV Line

This practical example demonstrates using AppendUint to efficiently build a CSV line containing numeric data.

csv_builder.go

package main

import ( “fmt” “strconv” )

func main() { values := []uint64{100, 200, 300, 400, 500} buf := []byte(“ID,Value\n”)

for i, v := range values {
    buf = strconv.AppendUint(buf, uint64(i+1), 10)
    buf = append(buf, ',')
    buf = strconv.AppendUint(buf, v, 10)
    buf = append(buf, '\n')
}

fmt.Println(string(buf))

}

We build a CSV header and rows with sequential IDs and values. AppendUint efficiently converts numbers to their string representation in the buffer.

Source

Go strconv package documentation

This tutorial covered the strconv.AppendUint function in Go with practical examples of unsigned integer to byte slice conversion.

Author

My name is Jan Bodnar, and I am a passionate programmer with extensive programming experience. I have been writing programming articles since 2007. To date, I have authored over 1,400 articles and 8 e-books. I possess more than ten years of experience in teaching programming.

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