Golang strconv.FormatInt

last modified April 20, 2025

This tutorial explains how to use the strconv.FormatInt function in Go. We’ll cover integer-to-string conversion basics with practical examples.

The strconv.FormatInt function converts an integer to a string. It’s one of the most commonly used functions in Go for formatting numeric output.

FormatInt allows specifying the base for conversion (2-36). The function returns the string representation of the integer in the specified base.

Basic strconv.FormatInt Example

The simplest use of strconv.FormatInt converts an integer to a base 10 string. Here we demonstrate basic conversion.

basic_formatint.go

package main

import ( “fmt” “strconv” )

func main() { num := int64(42) str := strconv.FormatInt(num, 10)

fmt.Printf("Integer %d converted to string '%s'\n", num, str)

}

We convert the integer 42 to a base 10 string. The function takes an int64 value and returns its string representation in the specified base.

Converting to Different Bases

strconv.FormatInt supports conversion to various bases. This example shows conversions to binary, octal, decimal, and hexadecimal.

different_bases.go

package main

import ( “fmt” “strconv” )

func main() { num := int64(42)

fmt.Println("Binary:", strconv.FormatInt(num, 2))
fmt.Println("Octal:", strconv.FormatInt(num, 8))
fmt.Println("Decimal:", strconv.FormatInt(num, 10))
fmt.Println("Hexadecimal:", strconv.FormatInt(num, 16))

}

We convert the same number to different bases. Base 2 gives binary, 8 gives octal, 10 gives decimal, and 16 gives hexadecimal representation.

Handling Negative Numbers

strconv.FormatInt properly handles negative numbers. This example demonstrates conversion of negative values.

negative_numbers.go

package main

import ( “fmt” “strconv” )

func main() { num := int64(-42)

fmt.Println("Decimal:", strconv.FormatInt(num, 10))
fmt.Println("Hexadecimal:", strconv.FormatInt(num, 16))
fmt.Println("Binary:", strconv.FormatInt(num, 2))

}

Negative numbers are converted with a leading minus sign. The base conversion works the same way as with positive numbers.

FormatInt vs Itoa

strconv.Itoa is a simpler alternative for base 10 conversion. This example compares FormatInt and Itoa.

formatint_vs_itoa.go

package main

import ( “fmt” “strconv” )

func main() { num := int64(42)

// Using FormatInt for base 10
str1 := strconv.FormatInt(num, 10)
fmt.Println("FormatInt:", str1)

// Using Itoa (only for base 10)
str2 := strconv.Itoa(int(num))
fmt.Println("Itoa:", str2)

}

Itoa is more convenient for base 10 conversion of int values. FormatInt is needed for other bases or when working with int64.

Performance Considerations

For performance-critical code, understanding conversion costs is important. This example benchmarks FormatInt against alternatives.

performance.go

package main

import ( “fmt” “strconv” “time” )

func main() { const iterations = 1000000 num := int64(12345)

// Benchmark FormatInt
start := time.Now()
for i := 0; i < iterations; i++ {
    strconv.FormatInt(num, 10)
}
fmt.Println("FormatInt duration:", time.Since(start))

// Benchmark fmt.Sprintf
start = time.Now()
for i := 0; i < iterations; i++ {
    fmt.Sprintf("%d", num)
}
fmt.Println("Sprintf duration:", time.Since(start))

}

FormatInt is significantly faster than fmt.Sprintf for integer-to-string conversion. Use FormatInt when performance matters.

Alternative: fmt.Sprintf

fmt.Sprintf provides another way to format integers as strings. This example compares it with FormatInt.

sprintf.go

package main

import ( “fmt” “strconv” )

func main() { num := int64(42)

// Using FormatInt
str1 := strconv.FormatInt(num, 10)
fmt.Println("FormatInt result:", str1)

// Using Sprintf
str2 := fmt.Sprintf("%d", num)
fmt.Println("Sprintf result:", str2)

}

Sprintf is more flexible but slower than FormatInt. Use FormatInt for simple conversions and Sprintf when you need complex formatting.

Practical Example: Number Formatting

This practical example demonstrates using FormatInt to create formatted number strings with padding and different bases.

number_formatting.go

package main

import ( “fmt” “strconv” “strings” )

func main() { numbers := []int64{7, 42, 255, 1024, 65535}

for _, num := range numbers {
    // Format with leading zeros
    dec := strconv.FormatInt(num, 10)
    dec = fmt.Sprintf("%06s", dec)
    
    // Format as hexadecimal
    hex := strconv.FormatInt(num, 16)
    hex = strings.ToUpper(hex)
    hex = fmt.Sprintf("0x%04s", hex)
    
    fmt.Printf("%d → Dec: %s, Hex: %s\n", num, dec, hex)
}

}

We format numbers with leading zeros and hexadecimal prefixes. FormatInt provides the base conversion, while fmt.Sprintf handles the padding.

Source

Go strconv package documentation

This tutorial covered the strconv.FormatInt function in Go with practical examples of integer-to-string conversion in various scenarios.

Author

My name is Jan Bodnar, and I am a passionate programmer with extensive programming experience. I have been writing programming articles since 2007. To date, I have authored over 1,400 articles and 8 e-books. I possess more than ten years of experience in teaching programming.

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